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 Corollary to the Triangle Exterior Angle Theorem: 
The measure of an exterior angle of a triangle is 
greater than the measure of each of its remote 
interior angles. 
2 
3 
1 
m<1 > m<2 and m<1 > m<3
 m<2 = m<1 by the Isosceles Triangle Theorem. Explain 
why m<2 > m>3. 
1 
2 
4 
3 
m<1 > m<3 + m<4 because 
<1 is the exterior angle, so 
m<1 > m<3. 
By substitution property, m< 2 > m<3, 
since m<2 = m<1.
 If two sides of a triangle are not congruent, then the 
larger angle lies opposite the longer side. 
X 
Y 
11 12 
14 Z 
<Y is the largest angle.
 A landscape architect is designing a triangular deck. 
She wants to place benches in the two larger corners. 
Which corners have the larger angles? 
27ft 
21ft 
A 
18ft 
B 
C 
<B and <A are the larger angles, <C is the smallest.
 If two sides of a triangle are not congruent, then the 
longer side lies opposite the larger angle. 
X 
Y 
Z 
48 
98 
34 
XZ is the longest side.
 Which side is the shortest? 
66 
TV is the shortest side. 
52 62 
U 
T 
V 
40 
60 
X 
Y 
Z 
80 
YZ is the shortest side
 Triangle Inequality Theorem: 
The sum of the lengths of any two sides of a 
triangle is greater than the length of the third side. 
a 
b 
c a + b > c 
b + c > a 
c + a > b
 Can a triangle have sides with the given lengths? 
 3ft, 7ft, 8ft 
Yes, 3 + 7 = 10 and 10 > 8 
 3cm, 6cm, 10cm 
No, 3 + 6 = 9 and 9 is not greater than 10
 Can a triangle have sides with the given lengths? 
 2m, 7m, 9m 
No, 2 + 7 = 9, and 9 is not greater than 9 
 4yd, 6yd, 9yd 
Yes, 4 + 6 = 10 and 10 is greater than 9
 A triangle has side lengths of 8cm and 10cm. Describe 
the possible lengths of the third side. 
To answer this kind of question, add the numbers together and 
Subtract the small number from the larger number. 
8 + 10 = 18 10 – 8 = 2 
The value of the third side must be greater 
Than 2 and less than 18. 
(x > 2 and x < 18) 
2cm < x < 18cm
 A triangle has side lengths of 3in and 12in. Describe 
the possible lengths of the third side. 
To answer this kind of question, add the numbers together and 
Subtract the small number from the larger number. 
3 + 12 = 15 12 – 3 = 9 
The value of the third side must be greater 
Than 9 and less than 15. (x > 9 and x < 15) 
9in < x < 15in
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