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A tf.Tensor represents a multidimensional array of elements.
tf.Tensor(
*args, **kwargs
)
All elements are of a single known data type.
When writing a TensorFlow program, the main object that is
manipulated and passed around is the tf.Tensor.
A tf.Tensor has the following properties:
- a single data type (float32, int32, or string, for example)
- a shape
TensorFlow supports eager execution and graph execution. In eager execution, operations are evaluated immediately. In graph execution, a computational graph is constructed for later evaluation.
TensorFlow defaults to eager execution. In the example below, the matrix multiplication results are calculated immediately.
# Compute some values using a Tensorc = tf.constant([[1.0, 2.0], [3.0, 4.0]])d = tf.constant([[1.0, 1.0], [0.0, 1.0]])e = tf.matmul(c, d)print(e)tf.Tensor([[1. 3.][3. 7.]], shape=(2, 2), dtype=float32)
Note that during eager execution, you may discover your Tensors are actually
of type EagerTensor. This is an internal detail, but it does give you
access to a useful function, numpy:
type(e)<class '...ops.EagerTensor'>print(e.numpy())[[1. 3.][3. 7.]]
In TensorFlow, tf.functions are a common way to define graph execution.
A Tensor's shape (that is, the rank of the Tensor and the size of
each dimension) may not always be fully known. In tf.function
definitions, the shape may only be partially known.
Most operations produce tensors of fully-known shapes if the shapes of their inputs are also fully known, but in some cases it's only possible to find the shape of a tensor at execution time.
A number of specialized tensors are available: see tf.Variable,
tf.constant, tf.placeholder, tf.sparse.SparseTensor, and
tf.RaggedTensor.
a = np.array([1, 2, 3])
b = tf.constant(a)
a[0] = 4
print(b) # tf.Tensor([4 2 3], shape=(3,), dtype=int64)
For more on Tensors, see the guide.
Attributes |
|---|
device
dtype
DType of elements in this tensor.
graph
name
ndim
op
shape
tf.TensorShape that represents the shape of this tensor.t = tf.constant([1,2,3,4,5])t.shapeTensorShape([5])
tf.Tensor.shape is equivalent to tf.Tensor.get_shape().
In a tf.function or when building a model using
tf.keras.Input, they return the build-time shape of the
tensor, which may be partially unknown.
A tf.TensorShape is not a tensor. Use tf.shape(t) to get a tensor
containing the shape, calculated at runtime.
See tf.Tensor.get_shape(), and tf.TensorShape for details and examples.
value_index
Methods
consumers
consumers()
(self: handle) -> list
eval
eval(
feed_dict=None, session=None
)
Evaluates this tensor in a Session.
Calling this method will execute all preceding operations that produce the inputs needed for the operation that produces this tensor.
| Args |
|---|
feed_dict
Tensor objects to feed values. See
tf.Session.run for a description of the valid feed values.
session
Session to be used to evaluate this tensor. If
none, the default session will be used.
| Returns | |
|---|---|
| A numpy array corresponding to the value of this tensor. |
experimental_ref
experimental_ref()
DEPRECATED FUNCTION
get_shape
get_shape()
Returns a tf.TensorShape that represents the shape of this tensor.
In eager execution the shape is always fully-known.
a = tf.constant([[1.0, 2.0, 3.0], [4.0, 5.0, 6.0]])print(a.shape)(2, 3)
tf.Tensor.get_shape() is equivalent to tf.Tensor.shape.
When executing in a tf.function or building a model using
tf.keras.Input, Tensor.shape may return a partial shape (including
None for unknown dimensions). See tf.TensorShape for more details.
inputs = tf.keras.Input(shape = [10])# Unknown batch sizeprint(inputs.shape)(None, 10)
The shape is computed using shape inference functions that are
registered for each tf.Operation.
The returned tf.TensorShape is determined at build time, without
executing the underlying kernel. It is not a tf.Tensor. If you need a
shape tensor, either convert the tf.TensorShape to a tf.constant, or
use the tf.shape(tensor) function, which returns the tensor's shape at
execution time.
This is useful for debugging and providing early errors. For
example, when tracing a tf.function, no ops are being executed, shapes
may be unknown (See the Concrete Functions
Guide for details).
@tf.functiondef my_matmul(a, b):result = a@b# the `print` executes during tracing.print("Result shape: ", result.shape)return result
The shape inference functions propagate shapes to the extent possible:
f = my_matmul.get_concrete_function(tf.TensorSpec([None,3]),tf.TensorSpec([3,5]))Result shape: (None, 5)
Tracing may fail if a shape missmatch can be detected:
cf = my_matmul.get_concrete_function(tf.TensorSpec([None,3]),tf.TensorSpec([4,5]))Traceback (most recent call last):ValueError: Dimensions must be equal, but are 3 and 4 for 'matmul' (op:'MatMul') with input shapes: [?,3], [4,5].
In some cases, the inferred shape may have unknown dimensions. If
the caller has additional information about the values of these
dimensions, tf.ensure_shape or Tensor.set_shape() can be used to augment
the inferred shape.
@tf.functiondef my_fun(a):a = tf.ensure_shape(a, [5, 5])# the `print` executes during tracing.print("Result shape: ", a.shape)return a
cf = my_fun.get_concrete_function(tf.TensorSpec([None, None]))Result shape: (5, 5)
| Returns | |
|---|---|
A tf.TensorShape representing the shape of this tensor.
|
ref
ref()
Returns a hashable reference object to this Tensor.
The primary use case for this API is to put tensors in a set/dictionary.
We can't put tensors in a set/dictionary as tensor.__hash__() is no longer
available starting Tensorflow 2.0.
The following will raise an exception starting 2.0
x = tf.constant(5)y = tf.constant(10)z = tf.constant(10)tensor_set = {x, y, z}Traceback (most recent call last):TypeError: Tensor is unhashable. Instead, use tensor.ref() as the key.tensor_dict = {x: 'five', y: 'ten'}Traceback (most recent call last):TypeError: Tensor is unhashable. Instead, use tensor.ref() as the key.
Instead, we can use tensor.ref().
tensor_set = {x.ref(), y.ref(), z.ref()}x.ref() in tensor_setTruetensor_dict = {x.ref(): 'five', y.ref(): 'ten', z.ref(): 'ten'}tensor_dict[y.ref()]'ten'
Also, the reference object provides .deref() function that returns the
original Tensor.
x = tf.constant(5)x.ref().deref()<tf.Tensor: shape=(), dtype=int32, numpy=5>
set_shape
set_shape(
shape
)
Updates the shape of this tensor.
With eager execution this operates as a shape assertion. Here the shapes match:
t = tf.constant([[1,2,3]])t.set_shape([1, 3])
Passing a None in the new shape allows any value for that axis:
t.set_shape([1,None])An error is raised if an incompatible shape is passed.
t.set_shape([1,5])Traceback (most recent call last):ValueError: Tensor's shape (1, 3) is not compatible with suppliedshape [1, 5]
When executing in a tf.function, or building a model using
tf.keras.Input, Tensor.set_shape will merge the given shape with
the current shape of this tensor, and set the tensor's shape to the
merged value (see tf.TensorShape.merge_with for details):
t = tf.keras.Input(shape=[None, None, 3])print(t.shape)(None, None, None, 3)
Dimensions set to None are not updated:
t.set_shape([None, 224, 224, None])print(t.shape)(None, 224, 224, 3)
The main use case for this is to provide additional shape information that cannot be inferred from the graph alone.
For example if you know all the images in a dataset have shape [28,28,3] you
can set it with tf.set_shape:
@tf.functiondef load_image(filename):raw = tf.io.read_file(filename)image = tf.image.decode_png(raw, channels=3)# the `print` executes during tracing.print("Initial shape: ", image.shape)image.set_shape([28, 28, 3])print("Final shape: ", image.shape)return image
Trace the function, see the Concrete Functions Guide for details.
cf = load_image.get_concrete_function(tf.TensorSpec([], dtype=tf.string))Initial shape: (None, None, 3)Final shape: (28, 28, 3)
Similarly the tf.io.parse_tensor function could return a tensor with
any shape, even the tf.rank is unknown. If you know that all your
serialized tensors will be 2d, set it with set_shape:
@tf.functiondef my_parse(string_tensor):result = tf.io.parse_tensor(string_tensor, out_type=tf.float32)# the `print` executes during tracing.print("Initial shape: ", result.shape)result.set_shape([None, None])print("Final shape: ", result.shape)return result
Trace the function
concrete_parse = my_parse.get_concrete_function(tf.TensorSpec([], dtype=tf.string))Initial shape: <unknown>Final shape: (None, None)
Make sure it works:
t = tf.ones([5,3], dtype=tf.float32)serialized = tf.io.serialize_tensor(t)print(serialized.dtype)<dtype: 'string'>print(serialized.shape)()t2 = concrete_parse(serialized)print(t2.shape)(5, 3)
# Serialize a rank-3 tensort = tf.ones([5,5,5], dtype=tf.float32)serialized = tf.io.serialize_tensor(t)# The function still runs, even though it `set_shape([None,None])`t2 = concrete_parse(serialized)print(t2.shape)(5, 5, 5)
| Args |
|---|
shape
TensorShape representing the shape of this tensor, a
TensorShapeProto, a list, a tuple, or None.
| Raises |
|---|
ValueError
shape is not compatible with the current shape of
this tensor.
__abs__
__abs__(
name=None
)
Computes the absolute value of a tensor.
Given a tensor of integer or floating-point values, this operation returns a tensor of the same type, where each element contains the absolute value of the corresponding element in the input.
Given a tensor x of complex numbers, this operation returns a tensor of type
float32 or float64 that is the absolute value of each element in x. For
a complex number \(a + bj\), its absolute value is computed as
\(\sqrt{a^2 + b^2}\).
For example:
# real numberx = tf.constant([-2.25, 3.25])tf.abs(x)<tf.Tensor: shape=(2,), dtype=float32,numpy=array([2.25, 3.25], dtype=float32)>
# complex numberx = tf.constant([[-2.25 + 4.75j], [-3.25 + 5.75j]])tf.abs(x)<tf.Tensor: shape=(2, 1), dtype=float64, numpy=array([[5.25594901],[6.60492241]])>
| Args |
|---|
x
Tensor or SparseTensor of type float16, float32, float64,
int32, int64, complex64 or complex128.
name
| Returns | |
|---|---|
A Tensor or SparseTensor of the same size, type and sparsity as x,
with absolute values. Note, for complex64 or complex128 input, the
returned Tensor will be of type float32 or float64, respectively. |
If x is a SparseTensor, returns
SparseTensor(x.indices, tf.math.abs(x.values, ...), x.dense_shape)
__add__
__add__(
y
)
The operation invoked by the Tensor.add operator.
| Purpose in the API | |
|---|---|
This method is exposed in TensorFlow's API so that library developers
can register dispatching for Tensor.add to allow it to handle
custom composite tensors & other custom objects. |
The API symbol is not intended to be called by users directly and does appear in TensorFlow's generated documentation.
| Args |
|---|
x
+ operator.
y
+ operator.
name
| Returns | |
|---|---|
The result of the elementwise + operation.
|
__and__
__and__(
y
)
__array__
__array__(
dtype=None
)
__bool__
__bool__()
Dummy method to prevent a tensor from being used as a Python bool.
This overload raises a TypeError when the user inadvertently
treats a Tensor as a boolean (most commonly in an if or while
statement), in code that was not converted by AutoGraph. For example:
if tf.constant(True): # Will raise.
# ...
if tf.constant(5) < tf.constant(7): # Will raise.
# ...
| Raises | |
|---|---|
TypeError.
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__div__
__div__(
y
)
Divides x / y elementwise (using Python 2 division operator semantics). (deprecated)
This function divides x and y, forcing Python 2 semantics. That is, if x
and y are both integers then the result will be an integer. This is in
contrast to Python 3, where division with / is always a float while division
with // is always an integer.
| Args |
|---|
x
Tensor numerator of real numeric type.
y
Tensor denominator of real numeric type.
name
| Returns | |
|---|---|
x / y returns the quotient of x and y.
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Migrate to TF2
This function is deprecated in TF2. Prefer using the Tensor division operator,
tf.divide, or tf.math.divide, which obey the Python 3 division operator
semantics.
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