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arrayfreq.java
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93 lines (82 loc) · 2.34 KB
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import java.util.Arrays;
import java.util.Scanner;
public class arrayfreq {
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
System.out.println("enter the size of array");
int n =sc.nextInt();
int arr[]=new int[n];
int dup[]=new int[n];
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
dup[i]=-1;
}
for(int i=0;i<arr.length;i++)
{
int count=1;
for(int j=i+1;j<arr.length;j++)
{
if(arr[i]==arr[j])
{
count++;
//eg 1 2 1 array hai toh vo ek baar 1 ko 2 baar count krega,2 ko 1 baar,aur 1 v dubara1 count krega....
//aisa naa krne ke liye we write next statement
dup[j]=0;
}
}
//ek Element array mein kitni baar aarha.
if(dup[i]!=0)
{
dup[i]=count;
}
}
System.out.println("frequency of each elelemnt is");
for(int i=0;i<n;i++)
{
if(dup[i]!=0)
{
System.out.println(arr[i]+" comes "+dup[i]+" times");
}
}
// method 2
int max = arr[0];
System.out.println("2nd method");
for (int i = 1; i < arr.length; i++)
{
if (arr[i] > max)
max = arr[i];
}
int temp[]=new int[max+1];
for(int j=0;j<n;j++)
{
temp[arr[j]]++;
}
for(int i=0;i<n;i++)
{
if(temp[arr[i]]>0)
{
System.out.println(arr[i]+" comes "+temp[arr[i]]+" times");
temp[arr[i]]=0;
}
}
//method 3 hashmap
System.out.println("3rd method");
java.util.HashMap<Integer,Integer> h=new java.util.HashMap<>();
for(int i=0;i<n;i++)
{
if(h.containsKey(arr[i]))
{
h.put(arr[i],h.get(arr[i])+1);
}
else
{
h.put(arr[i],1);
}
}
for (int i : h.keySet()) {
System.out.println("key: " + i + " value: " + h.get(i));
}
}
}