package com.hmkcode;

import java.util.Arrays;

import java.util.LinkedList;

import java.util.List;

import java.util.stream.Collectors;

import java.util.stream.Stream;

public class App

{

public static void main( String[] args )

{

String[] arr = new String[]{"a", "b", "c", "d"};

Stream<String> stream = Arrays.stream(arr);

stream = Stream.of("a", "b", "c", "d");

List<String> list = new LinkedList<String>();

list.add("a");

list.add("b");

stream = list.stream();

// forEach()

stream = Stream.of("a", "b", "c", "d");

stream.forEach(e -> System.out.println(e));

// distinct() | count()

stream = Stream.of("a", "b", "c", "d");

System.out.println(stream.distinct().count());

// anyMatch()

stream = Stream.of("a", "b", "c", "d");

System.out.println(stream.anyMatch(e -> e.contains("a")));

// filter()

stream = Stream.of("a", "b", "c", "d");

stream.filter(e -> e.contains("b")).forEach(e -> System.out.println(e));

// map()

stream = Stream.of("a", "b", "c", "d");

stream.map(e -> e.toUpperCase()).forEach(e -> System.out.println(e));

// flatMap()

stream = getBigList().stream().flatMap(lst -> lst.stream());

stream.forEach(e -> System.out.println(e));

//[any|all|none]Match()

System.out.println(Stream.of("a", "b", "c", "d").allMatch( e -> (e.length() == 1)));

System.out.println(Stream.of("a", "b", "c", "d").noneMatch(e -> (e.length() == 2)));

System.out.println(Stream.of("a", "b", "c", "d").anyMatch( e -> e.equals("a") ));

//reduce()

stream = Stream.of("a", "b", "c", "d");

System.out.println(stream.reduce("", (x,y) -> apply(x,y)));

//collect(Collectors)

stream = Stream.of("a", "b", "c", "d");

System.out.println(stream.collect(Collectors.toList()));

}

private static String apply(String a, String b){

System.out.println(a+"->"+b);

return a+b;

}

private static List<List<String>> getBigList(){

List<List<String>> bigList = new LinkedList<List<String>>();

List<String> list1 = new LinkedList<String>();

list1.add("a");

list1.add("b");

List<String> list2 = new LinkedList<String>();

list2.add("c");

list2.add("d");

bigList.add(list1);

bigList.add(list2);

return bigList;

}

}